Problem
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Seven Apple woman, possessing respectively 20,40,60,80,100,120 and 140
apples, went to market and sold all their apples at the same price, and
each received the same sum of money. What was the price?


Answer
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Each woman sold her apples at seven for $0.1 and $0.3 each for the odd 
ones over. thus, each received the same amount, $2. Without questioning the
ingenuity of the thing, I have always thought the soulution unsatisfactory,
because really inderminate, even if we admit that such an eccentric way of
selling may be fairly termed a 'price'. It would seem just as fair if they
sold them at different rates and afterwaeds divided the money; or sold different 
kinds of apples at different values; or sold the same rate per basketful; or sold
by weight , the apples being of different sizes; and so on. That is why
I have never held a high opinion of this old puzzle.
In a general way, we can say that n women, possesing 
an+(n-1),n(a+b)+(n-2),n(a+2b)+(n-3),..,n[a+b(n-1)] apples respectively, can sell
 at n for a penny and b pennies for each odd one over and each receive a+b(n-1) pennies. 
In the case of our puzzles a=2, b=3 and n=7.